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Here is an opportunity to help your student get ready for the test by---
- finding out what to expect on the test
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- reviewing the content that the test covers
I am offering one-on-one ACT test preparation. Recommended time commitment is at least 4 hours. Can be split over multiple sessions.
Cost: $30.00 per hour. Includes materials.
To register, fill out the contact form on the right.
Tuesday, December 4, 2018
Tuesday, November 27, 2018
New Worksheet - Math - Practice with Negative Numbers (II)
Rewrite first as an addition. Then calculate the answer.
(+22) – (-32) = __________________ __________________
(-505) – (+56) = __________________ __________________
(+302) – (+25) = __________________ __________________
(-269) – (+341) = __________________ __________________
(-51) – (-26) = __________________ __________________
(+55) – (-21) = __________________ __________________
(+312) – (-208) = __________________ __________________
(+242) – (+241) = __________________ __________________
(-53) – (+12) = __________________ __________________
(-26) – (-605) = __________________ __________________
(-252) – (-261) = __________________ __________________
Answer the following word problems.
Mr. Jenzen pays off $320 of debt to his bank account. After the payment is made, he still shows a negative balance of $344. How much was he in debt before he made the payment?
Answer: __________________
The water level of the Dead Sea is at 560 meters below sea level. The deepest spot of the Dead Sea is at 800 meters below sea level. How deep is the Dead Sea at the spot?
Answer: __________________
On a day in March the temperature at noon in Tobolsk, Siberia is –15 degrees Celsius. At night the temperature sinks to –24.5 degrees Celsius. What is the temperature difference?
Answer: __________________
Rewrite each problem without the parentheses and then solve.
(+63) + (-25) – (-22) – (+250) = _____________________________ __________________
(-332) – (+154) – (-321) + (-435) = _____________________________ __________________
(-123) + (-11) – (62) – (-34) = _____________________________ __________________
(+54) – (+36) + (-66) – (-326) = _____________________________ __________________
© 2018 Laura Glassel – lizzietutoring.blogspot.com
(+22) – (-32) = __________________ __________________
(-505) – (+56) = __________________ __________________
(+302) – (+25) = __________________ __________________
(-269) – (+341) = __________________ __________________
(-51) – (-26) = __________________ __________________
(+55) – (-21) = __________________ __________________
(+312) – (-208) = __________________ __________________
(+242) – (+241) = __________________ __________________
(-53) – (+12) = __________________ __________________
(-26) – (-605) = __________________ __________________
(-252) – (-261) = __________________ __________________
Answer the following word problems.
Mr. Jenzen pays off $320 of debt to his bank account. After the payment is made, he still shows a negative balance of $344. How much was he in debt before he made the payment?
Answer: __________________
The water level of the Dead Sea is at 560 meters below sea level. The deepest spot of the Dead Sea is at 800 meters below sea level. How deep is the Dead Sea at the spot?
Answer: __________________
On a day in March the temperature at noon in Tobolsk, Siberia is –15 degrees Celsius. At night the temperature sinks to –24.5 degrees Celsius. What is the temperature difference?
Answer: __________________
Rewrite each problem without the parentheses and then solve.
(+63) + (-25) – (-22) – (+250) = _____________________________ __________________
(-332) – (+154) – (-321) + (-435) = _____________________________ __________________
(-123) + (-11) – (62) – (-34) = _____________________________ __________________
(+54) – (+36) + (-66) – (-326) = _____________________________ __________________
© 2018 Laura Glassel – lizzietutoring.blogspot.com
Tuesday, November 20, 2018
New Worksheet - Math - Substitution (II)
If x + y = 0, then solve the problems below.
1. If y = 8, evaluate: 2y + x + y + 11
What is the expression worth? _____________
2. If x = -10, evaluate: 4y + 5x + 2
What is the expression worth? _____________
3. If y = 8, evaluate: 4x + y – y + 7
What is the expression worth? _____________
4. If x = 10, evaluate: x + y + 7x + 5
What is the expression worth? _____________
5. If x = 7, evaluate: 8x + y + x + 9
What is the expression worth? _____________
6. If y = 5, evaluate: 9y + 8x + 10
What is the expression worth? _____________
7. If x = -5, evaluate: 4y + 7x + 9
What is the expression worth? _____________
8. If x = 6, evaluate: 6(x + y) + 6x + 11
What is the expression worth? _____________
9. If y = 11, evaluate: 4y + 9x + 6
What is the expression worth? _____________
10. If x = 7, evaluate: 6x – 3y + 5
What is the expression worth? _____________
© 2018 Laura Glassel – lizzietutoring.blogspot.com
Tuesday, November 13, 2018
New Worksheet - Math - Basic Algebra Practice (II)
Solve.
1. 77 - 6z = 27 - 7z + 10
Answer: ______________________
2. 64 + 8x = 6 + 7x + 61
Answer: ______________________
3. 91 (x + 10) = 317x
Answer: ______________________
4. 0.6 x + 0.2 (6) = 0.7 (x + 8)
Answer: ______________________
5. 7 (2 - 10 (x + 3)) = - x
Answer: ______________________
6. 7 (7 - 4 (x + 5)) = 60 x
Answer: ______________________
7. 3 ( 7 + 5 (x - 10)) = - 70
Answer: ______________________
8. 97 - 2x/11 = 9
Answer: ______________________
9. 71 - 27x = 8 + x / 6
Answer: ______________________
10. 19 - 8x = - 13 + x / 7
Answer: ______________________
11. Clarence is about to publish a new book. The publisher has given him two options: receiving $9,000 up front and 6% of the sales of the book or $29,000 up front and 2% of the sales of the book. What do the sales have to be for Clarence to make the same amount from each option?
Answer: ______________________
12. Louise walked past Thurman at a speed of 3 feet per second. After 8 seconds, Thurman started after her at a speed of 7 feet per second. How many seconds did it take Thurman to catch Louise?
Answer: ______________________
13. Michael has some ordinary mints that cost 60 cents per pound. If he wants to mix them with 10 pounds of minty mints that cost 90 cents per pound to create a mixture of "sorta minty mints" that cost 75 cents per pound, how much of the 60-cent candy must he use?
Answer: ______________________
14. The medieval spice merchant wants to blend some garlic powder, which costs 36 cents per pound, with 5 pounds of ground pepper, which costs 45 cents per pound, to create a big batch of medieval smelling salt worth exactly 40 cents per pound. How many pounds of the garlic powder should he use?
Answer: ______________________
15. Igor has a mixture containing 10% boric acid. He wants to combine this with 3 liters of a mixture containing 17% boric acid. How much of the 10% mixture must he use to create a combined mixture that has 14% boric acid?
Answer: ______________________
16. A 380-pound alloy containing 20% silver was mixed with an alloy containing 57% silver to get an alloy containing 40% silver. How many pounds of the 57% alloy were used?
Answer: ______________________
© 2018 Laura Glassel – lizzietutoring.blogspot.com
Tuesday, November 6, 2018
New Worksheet - Math - Simplyfing Single Variable Equations (II)
Simplify.
1. x/2 + x + 8(x-5)
Answer: ______________________
2. x + 3x + 6(x-8)
Answer: ______________________
3. x/9 + 10x + 9(x-5)
Answer: ______________________
4. x/9 + 3x + 5(x-5)
Answer: ______________________
5. x/3 + 3x + 7(x-1)
Answer: ______________________
6. 8x + (7-x) / 8 = 33
Answer: ______________________
7. 8x + (10-3x) / 5 = 8
Answer: ______________________
8. 9x + (1-4x) / 10 = 2
Answer: ______________________
9. x + (1-x) / 10 = 62
Answer: ______________________
10. 5x + (9-x) / 2 = 96
Answer: ______________________
11. 37x - 19 = 32 + x
Answer: ______________________
12. 10x - 10 = x + 63
Answer: ______________________
13. 4x - 5 = 5 + 25x
Answer: ______________________
14. 5x + 4 = 9x - 21
Answer: ______________________
15. 6x + 26 = 9x - 10
Answer: ______________________
© 2018 Laura Glassel – lizzietutoring.blogspot.com
Tuesday, October 30, 2018
New Worksheet - Word Problems - Newton's Second Law - Part 4
Solve the following word problems using this formula: force = mass x acceleration
1. A 47-kg water-skier is being pulled by a speedboat. The force causes her to accelerate at 9 m/s^2. What is the force?
___________________
2. How much force is needed to accelerate a 1200-kg elevator at 1.9 m/s^2?
___________________
3. What is the force needed to accelerate a 14-kg cart at 5.5 m/s^2?
___________________
4. Assume that a catcher in a professional baseball game exerts a force of 68.0 N to stop the ball. If the baseball has a mass of 0.213 kg, what is its acceleration as it is being caught?
___________________
5. A 428 kg boat is sinking in the ocean. The force of gravity that draws the boat down is partially offset by the buoyant force of the water, so that the net unbalanced force on the boat is 3100 N. What is the acceleration of the boat?
___________________
6. A house is lifted from its foundations onto a truck for relocation. The unbalanced force lifting the house is 2920 N. This force causes the house to move with an acceleration of 0.17 m/s2. What is the mass of the house?
___________________
© 2018 Laura Glassel – lizzietutoring.blogspot.com
Tuesday, October 23, 2018
New Worksheet - Word Problems - Newton's Second Law - Part 3
Solve the following word problems using this formula: force = mass x acceleration
1. The tallest man-made structure at present is the Warszawa Radio mast in Warsaw, Poland, This radio mast rises 646 m above the ground, nearly 200 m more than the Sears Tower in Chicago. Suppose a worker at the top of the Warszawa Radio mast accidentally knocks a tool off the tower. If the force acting on it is 7.9 N, and its acceleration is 9.8 m/s^2, what is the tool’s mass?
___________________
2. In drag racing, acceleration is more important than speed, and therefore drag racers are designed to provide high accelerations. Suppose a drag racer has a mass of 2510 kg and accelerates at a constant rate of 17.1 m/s^2. How large is the force acting on the racer?
___________________
3. What net force is required to accelerate a car at a rate of 4.57 m/s^2 if the car has a mass of 5900 kg?
___________________
4. A 8.65 kg bowling ball would require what force to accelerate down an alleyway at a rate of 7 m/s^2?
___________________
5. Sally has a car that accelerates at 6.9 m/s^2. If the car has a mass of 1950 kg, how much force does the car produce?
___________________
6. What is the mass of a truck if it produces a force of 81,000 N while accelerating at a rate of 9 m/s^2?
___________________
© 2018 Laura Glassel – lizzietutoring.blogspot.com
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