Understanding the Relationship
Gas stoichiometry combines the principles of chemical reactions with the properties of gases. In high school chemistry, you have already learned how to use the Ideal Gas Law (PV = nRT) to find properties of a single gas. Stoichiometry allows you to use the balanced chemical equation to relate the amount of one substance to another.
The key link between these two worlds is the mole (n). Stoichiometry uses mole ratios from balanced equations, and the Ideal Gas Law solves for moles based on pressure (P), volume (V), and temperature (T).
The Ideal Gas Law Formula: PV = nRT
P is Pressure (commonly in atm or kPa)
V is Volume (must be in Liters)
n is Number of Moles
R is the Ideal Gas Constant (0.0821 L atm / mol K or 8.314 L kPa / mol K)
T is Temperature (must be in Kelvin; K = Celsius + 273)
Steps for Gas Stoichiometry Problems
Write or check the balanced chemical equation.
Identify the given information. Is it gas data (P, V, T) or mass/mole data?
Convert your "Given" to Moles. If you start with gas data, use n = PV / RT. If you start with mass, use the molar mass.
Use the Mole Ratio from the balanced equation to find the moles of the "Unknown" substance.
Convert the Moles of the Unknown to the final units requested (Volume, Mass, or Pressure).
Practice Problems
The combustion of propane follows the equation: C3H8 + 5 O2 --> 3 CO2 + 4 H2O. If 5.00 grams of propane (C3H8) is burned, what volume of CO2 gas will be produced at 1.00 atm and 298 K?
Solid calcium carbonate decomposes into calcium oxide and carbon dioxide gas: CaCO3 --> CaO + CO2. How many grams of CaCO3 are needed to produce 15.0 L of CO2 at a pressure of 105 kPa and a temperature of 300 K?
Hydrogen gas is produced by reacting zinc with sulfuric acid: Zn + H2SO4 --> ZnSO4 + H2. If 12.0 grams of zinc react completely, what will be the pressure of the hydrogen gas if it is collected in a 4.00 L flask at 27 degrees Celsius?
In the reaction 2 NaN3 --> 2 Na + 3 N2, used in car airbags, how many grams of NaN3 are required to provide 65.0 L of nitrogen gas at 1.15 atm and 30 degrees Celsius?
Ammonia is produced via the Haber process: N2 + 3 H2 --> 2 NH3. If 20.0 L of nitrogen gas at 200 kPa and 500 K reacts with excess hydrogen, how many moles of ammonia are produced?
Answer Key
8.32 L of CO2
Steps: Convert 5.00g C3H8 to moles (0.113 mol). Use 3:1 ratio to get 0.339 mol CO2. Use V = nRT/P.
63.2 grams of CaCO3
Steps: Use n = PV/RT to find moles of CO2 (0.631 mol). Use 1:1 ratio to find moles of CaCO3. Multiply by molar mass (100.09 g/mol).
1.13 atm
Steps: Convert 12.0g Zn to moles (0.184 mol). Use 1:1 ratio to get 0.184 mol H2. Use P = nRT/V with T=300K.
130.5 grams of NaN3
Steps: Use n = PV/RT to find moles of N2 (3.01 mol). Use 2:3 ratio to find moles of NaN3 (2.007 mol). Multiply by molar mass (65.01 g/mol).
1.93 moles of NH3
Steps: Use n = PV/RT to find moles of N2 (0.963 mol). Use 2:1 mole ratio to find moles of NH3.